IMPORTANT TERMS
(i) Race: A competition in running, riding, swimming, cycling etc.
(iii) Starting Point: The point from which the race starts .
(iv) Winning Point (Post) : The last point at which race is completed.
(v) Dead Heat: A contest of race in which all the competitors set the same time and no one is winner.
(vi) A Game of Hundred: A game in which the players agree that whoever first score hundred points is the winner.
(vii) while A scores 100 points, B scores only 75 points, then we say that 'In a game of 100 A can give B 25 points'.
(viii) In a race of 100 metres A beats B by 20 metres, means while A runs 100 metres B runs 80 metres.
Question 1.
A istimes quicker than B. If A gives B a Start of 75 meters, Find the length of racecourse so that both of them reach the winning post at the same time.
(a) 100 m
(b) 150 m
(c) 200 m
(d) 180 m
(d) 180 m
Question 2.
In a game of Snooker, A can Give B 16 Points in 80 and A can Give C 15 point in 90. How many points can C give B in a game of 50?
(a) 10 Points
(b) 12 Points
(c) 5 Points
(d) 2 Points
(a) 10 m
(b) 20 m
(c) 25 m
(d) 12 m
(a) 400 m
(b) 300 m
(c) 350 m
(d) 500 M
(a) 150 m
(b) 120 m
(c) 125 m
(d) 180 m
Question 3.
P can run 100m in 20 second and Q in 25 seconds. P beats Q by(a) 10 m
(b) 20 m
(c) 25 m
(d) 12 m
Question 4.
In a 2 Km race, P can give Q 200 m and R 560 m. In the same race, Q can give R(a) 400 m
(b) 300 m
(c) 350 m
(d) 500 M
Question 5.
A runs 1.5 Times as fast as B can. If A gives B a start of 50 m, how far must the winning post be in order that A and B reach at the same time(a) 150 m
(b) 120 m
(c) 125 m
(d) 180 m
Question 6.
P and Q run a Kilometers and P win by 1 minutes. P and R run a kilometre and P wins by 375 m. Q and R run a kilometre and Q wins By 30 Seconds. Find the time taken by each runner to run a kilometre. (a) 150 sec, 210 sec, 240sec(b) 120 sec, 160 sec, 200sec
(c) 100 sec, 160 sec, 90sec
(d) 140 sec, 200 sec, 230sec
Question 7.
A can give B 25 point, A can give C 40 points and B can give C 20 Points. How many points make the game?(a) 120
(b) 100
(c) 150
(d) 80
Question 8.
At a game of billiard, A can give B 12 points in a game of 40 and A can give C 10 Points in game of 50. How many points can C and B in a game of 80?(a) 10
(b) 20
(c) 12
(d) 18
Question 9.
A can run 1 km in 5 minutes 48 seconds and B in 6 minutes. How many metres start can A give B in 1 km race so that the race may end in a dead heat?Question 10.
Question 11.
Question 12.
In a game of billiards, A can give B 10 points in 60 and he can give C 15 in 60.How many points can B give C in a game of 90?Question 13.
A can gives B 40 points, A can give C 64 points, and B can give C 30 points.How many points to make the game?Question 14.
Two men A and B walk around a circle 1500 metres in circumference. A walks at the rate of 140 metres, and B at the rate 80 metres per minute .if they start from the same point, and walk in the same direction, when will they be together again?Question 15.
Two men, A and B run a 10 km race on a course 400 m round.If their rates are 5: 4, how often does the winner pass the other?Question 16.
Three girls Seema, Kiran and Nitu walk around a circle 3 km in circumference at the rates of 200, 150 and 125 metres per minute respectively. if they all start together and walk in the same direction, when will they first be together again?Question 17.
A and B start from the same point and travel in the same direction around a circular track 3 km in circumference, If their speed is 200 and 150 metres a minute, when will they first together again at the starting point?(a) 40 min
(b) 55 min
(c) 1 hour
(d) 45 min
Question 18.
Two men, A and B run a 500 m race, A having 140 m start their speeds are 3 :4. Then, A wins By:(a) 10 m
(b) 20 m
(c) 40 m
(d) 60 m
Question 19.
in a race of 200 metres, A can give a start of 10 metres to A C give a start of 20 metres to B. The start that C can give to A, in the same race is(a) 30m
(b) 29 m
(c) 27 m
(d) 25 m
Question 20.
In a race of 300 metres A rates B by 15 metres or 5 seconds, Hoe much time A take to complete the race?(a) 105 sec.
(b) 100 sec.
(c) 95 sec.
(d) 90 sec.
Solutions:
Ans 1: 200 m
Ans 2: 2 Points
Ans 3: 20 m
Ans 4: 400 m
When Q run (2000 – 200)m, R runs(2000 – 560)m.
Ans 5: 150 m
Ans 6: 150 sec, 210 sec, 240sec
Ans 7: 100
Let the game be of x points.
When A scores x points, B scores X – 25 points, and C scores X – 40 Ponts
Ans 8: 10
When A scores 40 points, B scores (40 – 12) points.
When A scores 50 points, C scores (50 – 10) points.
When A scores 50 points, C scores (50 – 10) points.
Ans: 9
A can give B (6 minutes - 5 minutes 48 seconds) or 12 seconds start. Now we must find the distance B can run in 12 seconds.The distance run by B in 6 minutes = 1000 m
∴ The distance run by B in 12 seconds = 1000 x 12 / 6 x 60 = 100/3 = 33 1/3 m
∴ A can give B 33 1/3 metres' Start.
Ans: 10
A beats B by 1 minute (60 seconds) and B beats C by 30 Seconds∴ A beats C by ( 60 + 30) or 90 seconds
But A beats C by 375 m
∴ But A runs C by 375 m.
∴ C runs 1000 m in 90/375 x 1000 = 240 seconds = 4 minutes.
Ans: 11
While B runs 726 m, A runs 800 m. While C runs 550 m, B runs 600 m.. . While B runs 726m, C runs 550/600 x 726 = 665.5 m.
In a race of 800 m, A gives ( 800- 665.5) i.e. 134.5 m start to C, so in a race of 500 m A
gives 134.5/800x 500 m start to C i.e. 84.06 m start to C.
Ans: 12
A scores 60 while B scores 50, and C scores 45.. . B scores 90 while C scores 45/50 x 90 = 81
Hence, in a game of 90, B can give C ( 90-81) or 9 points .Let x points make the game, so that, according to the question,
if A has x points, then B has ( x-40) points.
B has x points, then C has ( x- 30) Points.
C has (x -64) points , then A has x points
. . By chain rule
x x ( x-64) = ( x- 40) ( x- 30)x
=> x2 - 64x = x2 - 70x + 1200
=> x = 2000
Hence, 200 points make the game
Ans: 13
Let x points make the game, so that , according to the question,
if A has x points, then B has ( x-40) points.
B has x points, then C has ( x- 30) Points.
C has (x -64) points , then A has x points
. . By chain rule
x x ( x-64) = ( x- 40) ( x- 30)x
=> x2 - 64x = x2 - 70x + 1200
=> x = 2000
Hence, 200 points make the game
Now A gains ( 140- 80) or 60 metres on B in 1 minute
. . A gains 1500 metres in 1500/60 or 25 minutes.
. . A passes B each time that a has runs 5 rounds i.6. 5 x 2/6 or 3 kms
. . ( 400m = 2/5 km)
Now 2 kms is contained 5 times in 10 kms
. . A passes B 5 times.
if A has x points, then B has ( x-40) points.
B has x points, then C has ( x- 30) Points.
C has (x -64) points , then A has x points
. . By chain rule
x x ( x-64) = ( x- 40) ( x- 30)x
=> x2 - 64x = x2 - 70x + 1200
=> x = 2000
Hence, 200 points make the game
Ans: 14
A and B will be together again for the first time when A has gained one complete round on B.Now A gains ( 140- 80) or 60 metres on B in 1 minute
. . A gains 1500 metres in 1500/60 or 25 minutes.
Ans 15
Since the rates are 5 :4 , a runs 5 rounds while B runs 4 rounds. . A passes B each time that a has runs 5 rounds i.6. 5 x 2/6 or 3 kms
. . ( 400m = 2/5 km)
Now 2 kms is contained 5 times in 10 kms
. . A passes B 5 times.
Ans 16
Seema is quickest girl one complete round on Neetu, the slowest girl, in 3000/200-125 or 40 minutes.Seema gains one complete round on Kiran, the next slowest girl in 3000/200-150 or 40 minutes.
Thus, Seema and Nitu are together after every 40 minutes, and Seema and Kiran are together after 60 minutes.
'Hence, Seema, Kiran and Nitu will be together in the time which is LCM of 40 and 60. The LCM of 40 and 60 is 120 minutes or 2 hours.
Ans 17. 1 hour
L.C.m of 15 min and 20 min = 60 min = 1 hr.
Hence, they will meet first together at the starting point after 1 hour.
Ans 18: 20 m
Here, greatest have to cover a distance of ( 500-140) = 360 m to reach the winning point while B 500 m Now, A covers 3m while B covers 4 m. . A covers 360 m while B covers 4/3 x 360 = 480 m
Hence, B will be ( 500- 480) = 20 m behind the winning post.
. . A wins by 20 min.
Ans 19: 29 m
B covers 200 m while A 190 mB covers 180 m while A 190/200x180 = 171 m
Hence, C covers 200 m while A = 171 m
So, C can give to A ( 200 - 171) = 29 m Start.
Ans 20: 95 sec.
From the question it is clear that speed of B = 15/5 = 3 m/sthe time taken by B to cover 300 m = 300 / 3 = 100 sec.
Hence, Time taken by A to complete the race = 100-5 = 95 sec.
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