Study the give table carefully to answer the following questions.
Percentage of marks obtained by 6 students in 6 Subjects .Subject / Student | Chemistry (Out of 150) | Maths (Out of 100) | Telugu (Out of 50) | English (Out of 100) | Physics (Out of 125) | Hindi (Out of 50) |
---|---|---|---|---|---|---|
A
|
85
|
62
|
72
|
68
|
70
|
70
|
B
|
65
|
68
|
66
|
69
|
80
|
80
|
C
|
70
|
72
|
68
|
78
|
60
|
|
D
|
80
|
78
|
76
|
82
|
90
|
58
|
E
|
90
|
80
|
72
|
66
|
70
|
76
|
F
|
60
|
74
|
62
|
54
|
60
|
64
|
1. What is the average marks obtained by all students in Hindi ?
- 34.5
- 32.3
- 34
- 36
- 33.6
2.What is the total marks obtained by B in all subjects together ?
- 407.5
- 390.5
- 508.5
- 408.75
- 404.5
3.What is F's overall percentage of marks in all subjects together ?
- 64.2%
- 60%
- 65.2%
- 62.33%
- 61.91%
4. If, to pass the examination , the minimum marks required in Chemistry is 120 and Physics is 95, then how many students will pass in both the subjects ?
- 3
- 1
- 4
- 2
- 5
5.Who among the following scored the highest marks in all subjects together ?
- B
- E
- D
- F
- A
Solutions and Answers :
1.1Total percentage of marks obtained by all students in Hindi = 70+80+66+58+76+64 = 414
Total Marks obtained by all students in Hindi = (50*414)/100 = 207
Average = 207/6 = 34.5
2.1
Marks obtained by B in all subjects together = (65*150)/100 + (68*100)/100 + (66*50)/100 + (69*100)/100 + (80*125)/100 + (80*50)/100 = 407.5
3.5
F's overall percentage of marks = (356*100)/575 = 61.91%
4.2
Pass percentage in chemistry = (120*100)/150 = 80%
Pass percentage in Physics = (95*100)/125 = 76%
From the above table Only D could pass in both subjects .
5.3
Calculate All students scores , you will find D got the highest marks in all subjects together .