Multiplying Factor:
1. When a quantity is increased:
Suppose, we have to increase 100 by 20%,
Then, Final value = 100+20% of 100
= 100+1/5 ✕100= 100+20= 120
Here, Multiplying factor(M.F.) =1.2
Solution: For 10% increase, M.F.1= 1.1
for 20% increase, M.F.2= 1.2
Therefore, New price= 5× 1.1× 1.2 = 5.5×1.2=6.60 R
Then, final value= 100-30% of 100
= 100-30= 70
Here, Multiplying factor (M.F.) = 0.7
Solution: Final Price= Original Price×MF1×MF2×MF3
⇒ = 10000×0.9×0.85×0.8 = 6120 D
10% decrease⇒ MF=0.9
5%increase ⇒MF=1.05
5%decrease ⇒ MF=0.95
Example:
Price of egg increase by 10% in December from previous month & again increases by 20% in January from December. Find the new price of the egg if the old price was 5R?Solution: For 10% increase, M.F.1= 1.1
for 20% increase, M.F.2= 1.2
Therefore, New price= 5× 1.1× 1.2 = 5.5×1.2=6.60 R
2. When quantity is decreased:
Suppose, we have to decrease 100 by 30%,Then, final value= 100-30% of 100
= 100-30= 70
Here, Multiplying factor (M.F.) = 0.7
Example:
There is 10%, 15% & 20% depreciation in the value of mobile phone in 1st, 2nd & 3rd month after sale if the price at beginning was 10,000R, then the price of mobile after 3rd month will be:-Solution: Final Price= Original Price×MF1×MF2×MF3
⇒ = 10000×0.9×0.85×0.8 = 6120 D
NOTE:
10% increase ⇒ MF=1.110% decrease⇒ MF=0.9
5%increase ⇒MF=1.05
5%decrease ⇒ MF=0.95
Example1:
If the numerator of a fraction is increased by 25% and the denominator is increased by 20%, the resultant fraction is 5/8. What was the original fraction?Solution:
Example2:
The population of a town is increased by 9.09% in the first year, decreased by 11.11% in 2nd year & increased by 14.28% in the 3rd year. Find the present population if after 3 years the population will become 512000.
Solution:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjkvYg9CEuuLpPUFOhzx6ymFCr5phRf7k4U6-yCIjaoRiDJ4Md3sJ_mIhgAzeJ4RpjbZ86U_taoJChX47SkzCMnvK-bhEHkAhjHc6wVwGE9B19w-tthO3iETk4bKg9yQdCGrtTIzRbmSBs/s400-rw/2.PNG)
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgh0wBpYnZxQ6wew8a7-Y7fbimbFRGdBfa9kgatKrVp1we_HR4PXOZZlSOIJbFMyCOTr_xcO3-Lyi3IGkH4qqasHCJ2ZbcPO5GAV1Pua5pNDOXCY2zC3BNHPY_M63fqxcWyLDl9kAV2eV4/s1600-rw/3.PNG)
Solution:
Note
Example1.
If selling price of 8 items is equal to the cost price of 9. Find percentage profit/loss?
Solution:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh0HqX-JYXFC3TTUfGnBfui2g80sn4_rMgIxWH2SsFXRhaCqeW22JDkN-5QQcT7xoQT5Wfi2y41EV_IQ-7TD-1R5sbt0Xi3tV_yWFY5PSj00WNyp-qX9ZqTenE_o0BL4mUWN5A5F3X4kuk/s400-rw/4.PNG)
Solution:
Example2:
If by selling 8 items one makes a loss of equal to Cost price of 2 items. Find percentage loss?
Solution:
Solution:
Example3:
How many oranges should be sold for Rs1 if they were purchased at rate of 6/Rs1 and a profit of 20% is desired.
Solution:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhCQ4dwEP51SnMmYFRGvlpNqn0gYj-1cGcPDc6e7JE_DUO7Qw2jCBho5sZspi4RVHwQZ0CKpCdhwS33q_hVky6o_dHUkB4ScMLyIZcoAg4hmR5Tw__j-OalczPC1JbqcyCaXsNlazT2las/s1600-rw/6.PNG)
Solution:
Example4:
If equal amount of Rupees were spent on two lots of bananas. One at a rate of Rs12/dozen and other at Rs18/dozen. If all the bananas are sold at the rate of Rs15/dozen. What is the percentage of profit/loss?
Solution: Faulty Balance:
Example1:
A milkman mixes 100 liter of water with every 800lit. Of milk and sells at a mark-up of 11.11%. Find the percentage profit?
Solution:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgHmj7Cy138WFTbeV7WcFA9u19CcOsrPY6LMhj6X5cOLqTOdYYxow6O-uXVNcHx59S6tImfMfb2HArrmbbckATFblpBFVuGiC3VZBlTDweCqY2jrwTWWzy_C8HycWR7VFYT-4vERAkhXD4/s1600-rw/8.PNG)
Solution:
Example2:
A meter scale is to measure 90cm. However, it expands 20% in summer. A trader sells at a mark-up of 10%, but he doesn’t know that the whole seller from where he has bought, measure 80cm only. Find percentage profit/loss of trader?
Solution:
Solution: